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Home/ Questions/Q 8696311
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T01:14:54+00:00 2026-06-13T01:14:54+00:00

Suppose this is my table: ID STRING 1 ‘ABC’ 2 ‘DAE’ 3 ‘BYYYYYY’ 4

  • 0

Suppose this is my table:

ID  STRING
1   'ABC'
2   'DAE'
3   'BYYYYYY'
4   'H'

I want to select all rows that have at least one of the characters in the STRING column somewhere in another row’s STRING variable.

For example, 1 and 2 have an A in common and 1 ad 3 have a B in common, but 4 does not have any characters in common with any of the other rows. So my query should return only the first three lines.

I don’t need to know with which line it matched.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T01:14:56+00:00Added an answer on June 13, 2026 at 1:14 am

    @A.B.Cade : Good solution but could be done without any distinct nor join.

    SELECT * FROM test t1
    WHERE EXISTS
    (
      SELECT * FROM test t2
      WHERE t1.id<>t2.id AND
      regexp_like(t1.string, '['|| replace(t2.string, '.[]', '\.\[\]')||']')
    )
    

    The query won’t compare the string with extra rows since it’ll stop the comparison as soon as 1 match is found for the current row…

    See fiddle.

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