Question

Suppose we have a menu which presents the user with some options:

Welcome:
1) Do something
2) Do something else
3) Do something cool
4) Quit

The user can press 1 – 4 and then the enter key. The program performs this operation and then presents the menu back to the user. An invalid option should just display the menu again.

I have the following main() method:

int main()
{
    while (true)
        switch (menu())
        {
            case 1:
                doSomething();
                break;
            case 2:
                doSomethingElse();
                break;
            case 3:
                doSomethingCool();
                break;
            case 4:
                return 0;
            default:
                continue;
        }
}

and the follwing menu():

int menu()
{
  cout << "Welcome:" << endl
       << "1: Do something" << endl
       << "2: Do something else" << endl
       << "3: Do something cool" << endl
       << "4: Quit" << endl;

  int result = 0;
  scanf("%d", &result);
  return result;
}

Entering numerical types works great. Entering 1 – 4 causes the program to perform the desired action, and afterwards the menu is displayed again. Entering a number outside this range such as -1 or 12 will display the menu again as expected.

However, entering something like ‘q’ will simply cause the menu to display over and over again infinitely, without even stopping to get the user input.

I don’t understand how this could possibly be happening. Clearly, menu() is being called as the menu is displayed over and over again, however scanf() is part of menu(), so I don’t understand how the program gets into this error state where the user is not prompted for their input.

I originally had cin >> result which did exactly the same thing.

Edit: There appears to be a related question, however the original source code has disappeared from pastebin and one of the answers links to an article which apparently once explained why this is happening, but is now a dead link. Maybe someone can reply with why this is happening rather than linking? 🙂

Edit: Using this example, here is how I solved the problem:

int getNumericalInput()
{
    string input = "";
    int result;

    while (true)
    {
        getline(cin, input);

        stringstream sStr(input);
        if (sStr >> result)
            return result;

        cout << "Invalid Input. Try again: ";
    }
}

and I simply replaced

int result = 0;
scanf("%d", &result);

with

int result = getNumericalInput();

Answer 1

When you try to convert the non-numeric input to a number, it fails and (the important part) leaves that data in the input buffer, so the next time you try to read an int, it’s still there waiting, and fails again — and again, and again, forever.

There are two basic ways to avoid this. The one I prefer is to read a string of data, then convert from that to a number and take the appropriate action. Typically you’ll use std::getline to read all the data up to the new-line, and then attempt to convert it. Since it will read whatever data is waiting, you’ll never get junk “stuck” in the input.

The alternative is (especially if a conversion fails) to use std::ignore to read data from the input up to (typically) the next new-line.