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Home/ Questions/Q 6925915
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:51:05+00:00 2026-05-27T10:51:05+00:00

suppose we have this class structure: public class BaseClass { public BaseClass() { Console.WriteLine(Base

  • 0

suppose we have this class structure:

public class BaseClass
{
    public BaseClass()
    {
        Console.WriteLine("Base class constructor has been called.");
    }
}

public class DerivedClass : BaseClass
{
    public DerivedClass()
    {
        Console.WriteLine("Derived class constructor has been called.");
    }
}

so, my question is simple: Why does C# let me to create an instance of the Base class using the constructor of the Derived Class?
for explample:
BaseClass instance = new DerivedClass();

I would also like to know what is the effect of doing it or what would the benefits be of doing that? I know that if I execute this code, the base class constructor gets called first and then the derived constructor because this follows the normal behavior of class inheritance.
thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:51:05+00:00Added an answer on May 27, 2026 at 10:51 am

    You aren’t; you’re creating an instance of DerivedClass and storing a reference to that instance within a variable whose type is BaseClass. Any variable in C# (or virtually any object-oriented language) that is of type T can hold a reference (or pointer, depending on your language) to any object whose type is T or a type that derives from T at some point.

    Doing this (in C#, anyway) has no effect whatsoever on how the object is constructed, so there is no “effect” in any strict sense.

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