Suppose x = range(20) k = 5 x_kth = x[::5] That gives me 0,5,10,15

Question

Asked: June 15, 20262026-06-15T11:30:54+00:00 2026-06-15T11:30:54+00:00

Suppose

x = range(20)
k = 5
x_kth = x[::5]

That gives me 0,5,10,15 etc
Is there any easy way to get the non kth elements in x?

x_nonkth = [1,2,3,4,6,7,8,9,11 etc

I know I can do

x_nonkth = [x[i] for i in range(len(x)) if i%k]

But I am looking for an easier way (and possibly faster?) if there is any.

You must login to add an answer.

Need An Account,

Editorial Team · Answer 1 · 2026-06-15T11:30:56+00:00

Editorial Team

You can make use of set difference: –

>>> x = range(20)
>>> k = 5
>>> list(set(x) - set(x[::k]))
[1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 16, 17, 18, 19]

The Archive Base Latest Questions