Question

Suppose you have a directory structure like this:

A/
   B/
      a.1
      b.2
      c.3

I’m wondering if there’s a way, knowing that B has no siblings AND NOT KNOWING B’s NAME, to do an os.listdir operation in one swoop (that is, without calling os.listdir twice), instead of in three commands like so:

root = "A"
secondLevel = os.listdir(root)[0]
listing = os.listdir(os.path.join(root,secondLevel))

Answer 1

import glob
os.listdir(glob.glob('A/*')[0])

or maybe even

glob.glob('A/*/*')