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Home/ Questions/Q 234237
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:10:07+00:00 2026-05-11T20:10:07+00:00

Supposing we have the following records in an SQL Server table. Date 19/5/2009 12:00:00

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Supposing we have the following records in an SQL Server table.

Date
19/5/2009 12:00:00 pm
19/5/2009 12:15:22 pm
20/5/2009 11:38:00 am

What is the SQL syntax for getting something like this one?

Date Count
19/5/2009 2
20/5/2009 1

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:10:07+00:00Added an answer on May 11, 2026 at 8:10 pm

    You need to do any grouping on a Date only version of your datefield, such as this.

    SELECT
        CONVERT(VARCHAR(10), YourDateColumn, 101),
        COUNT(*)
    FROM
        YourTable
    GROUP BY
        CONVERT(VARCHAR(10), YourDateColumn, 101)
    

    I usually do this though, as it avoids conversion to varchar.

    SELECT
        DATEPART(yy, YourDateColumn),
        DATEPART(mm, YourDateColumn),
        DATEPART(dd, YourDateColumn),
        COUNT(*)
    FROM
        YourTable
    GROUP BY
        DATEPART(yy, YourDateColumn),
        DATEPART(mm, YourDateColumn),
        DATEPART(dd, YourDateColumn)
    

    EDIT: Another way to get just the date part of a datetime

    DATEADD(d, 0, DATEDIFF(d, 0, YourDateColumn))
    
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