Question

    System.out.println("-----------------------------------------------------------");
    System.out.println("Please select a task");
    System.out.println("1: List employees with details");
    System.out.println("2: List of clients in state");
    System.out.println("3: List portfolio of client");
    System.out.println("4: Release an employee");
    System.out.println("5 Display stocks available for purchase/selling");
    System.out.println("6: Display client details");
    System.out.println("7: Buy Stock for client ");
    System.out.println("0: Exit program");
    System.out.println("-----------------------------------------------------------" + "\n" + "\n");

    System.out.print("Input:");

    Scanner scan = new Scanner(System.in);

    input = scan.nextInt();

    if (input == 1)
        {
        System.out.println("length of array list: " + employeeList.size());

        int index = 0;
        while ( index < employeeList.size() )
            {
            System.out.println(employeeList.get(index));
            index++;
            }
        }
    else if (input == 2)
        {
        String state_choice;
        System.out.println("Please enter the abbrivation for the state:");
        state_choice = scan.nextLine();

This is a portion from my current code I’m having issues at [else if (input == 2)] when I try to run it doesn’t let me input and just ignores it actually. I think its because of the “\n” from the previous entry. Is there a way to remove that “\n” or extra character without putting another scan.nextLine() before my entry? Didn’t really see anything in java docs..

Answer 1

Just add scan.nextLine(); after input = scan.nextInt();. The problem is within input = scan.nextInt();, it only reads integer number, so you need scan.nextLine(); to discard the new line \n generated by pressing Enter.