System.out.println(1 + 2 + "3");
Output:
33
System.out.println("1" + 2 + 3);
Output:
123
System.out.println(1 + 2 + 3); Output: 33 System.out.println(1 + 2 + 3); Output: 123
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System.out.println(1 + 2 + "3");
Output:
33
System.out.println("1" + 2 + 3);
Output:
123
Well, it’s a thing called order of operations.
1 + 2 is calculated to equal 3 and then the string “3” is appended to it converting the first 3 to a string and printing “33”.
In your second instance, “1” is already a string so adding numbers will convert them to strings to match, so appending “2” and then appending “3” and printing “123”.
P.S. Strings take precedence because they have a higher casting priority than integers do, therefore it will convert integers to strings but not strings to integers, as with the second example.