Question

Table 1 -> id, name
Table 2 -> id, name, text_value, table1_id, table3_id
Table 3 -> id, name

SELECT * FROM `table1`   
LEFT OUTER JOIN table2 ON table1.id = table2.table1_id   
WHERE 
 (
     (table2.table3_id = '7' AND table2.name like ('%test%'))
 )   
  AND 
 (
      table2.table3_id = '1' and table2.text_value like ('%fast update%'))
 )   
GROUP BY table1.id  
ORDER BY table1.id desc

Answer 1

Yes, but you need two joins to do so:

• Because you will be joining to table2 twice, one of the joins must
  use an alias. I chose t2.
• Change the AND to LEFT OUTER JOIN table2 AS t2 ON.
• In the remainder of the query, change table2 to t2.
• When you use GROUP BY, all the columns that you specify need to be in either the GROUP BY clause or an aggregate. Since you didn’t do that, and it is unclear why you tried to use GROUP BY, I am eliminating the GROUP BY clause.

There are several other changes. See final query below:

SELECT
  table1.id
FROM
  table1
    LEFT OUTER JOIN
  table2
    ON table1.id = table2.table1_id
    LEFT OUTER JOIN
  table2 t2
    ON table1.id = t2.table1_id
WHERE
  table2.table3_id = '7'
    and
  table2.name like '%test%'
    AND
  t2.table3_id = '1'
    and
  t2.text_value like '%fast update%'
ORDER BY
  table1.id DESC