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Home/ Questions/Q 7720541
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T03:42:05+00:00 2026-06-01T03:42:05+00:00

table: database1.comment id | owner_id | comment 1 | 1 | some words 2

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table: database1.comment
id | owner_id | comment    
1  |  1       | some words 
2  |  1       | some words
3  |  2       | some words

table: database2.users
id | display_name
1  | admin    
2  | guest

I am try to join 2 tables query, here is my php code:

$result = mysql_query("SELECT * FROM database1.comment INNER JOIN database2.users ON database1.comment.owner_id=database2.users.id order by database1.comment.id DESC");
while ($row = mysql_fetch_array($result)){
     echo '<li>'.$row['display_name'].': '.$row['comment'].'</li>';
}

I get a error message: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given. How to make a work code ( optimize way )

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  1. Editorial Team
    Editorial Team
    2026-06-01T03:42:07+00:00Added an answer on June 1, 2026 at 3:42 am

    If your query is invalid (or otherwise “failed”), mysql_query() returns “false” (instead of an array).

    SUGGESTIONS:

    1. Cut/paste your SQL string into MySQL, see what’s incorrect, and fix it. And that point, your PHP should be OK.

    2. Check your result (and gracefully handle any failures/errors) in your code:

    EXAMPLE (error: no “from” clause):

    $result = mysql_query('SELECT * WHERE 1=1');
    if (!$result) {
        die('Invalid query: ' . mysql_error());
    }
    
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