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Home/ Questions/Q 6131575
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:59:30+00:00 2026-05-23T16:59:30+00:00

Table: new_table user_number | diff 2 | 0 1 | 28 2 | 32

  • 0
Table:   
new_table                                                    
user_number  | diff                  
     2       |  0                      
     1       |  28  
     2       |  32  
     1       |  40  
     1       |  53  
     1       |  59  
     1       |  101  
     1       |  105  
     2       |  108  
     2       |  129  
     2       |  130    
     1       |  144  


            |(result)
            v

range  | number of users  
0-20   |  2  
21-41  |  3  
42-62  |  1  
63-83  |  2  
84-104 |  1  
105-135|  0  
136-156|  3


select t.range as [range], count(*) as [number of users]  
from (  
  select case    
    when diff between 0 and 20 then ' 0-20'  
    when diff between 21 and 41 then ' 21-41'  
    when diff between 42 and 62 then ' 42-62'  
    when diff between 63 and 83 then ' 63-83'  
    when diff between 84 and 104 then ' 84-104'  
    when diff between 105 and 135 then ' 105-135'  
    else '136-156'   
     end as range  
  from new_table) t  
group by t.diff  

Error:

You have an error in your SQL syntax, near '[range], count(*) as [number of users]  
from (  
  select case  
    when' at line 1  
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:59:31+00:00Added an answer on May 23, 2026 at 4:59 pm

    Mysql as a delimiter for keywords uses backtick sign ” ` “, not square brackets (like sql server)

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