Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6328181
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T17:24:48+00:00 2026-05-24T17:24:48+00:00

Table Users : user_id , credits_available Table Survey : user_id, survey_id, credits_required Now I

  • 0
Table Users : user_id , credits_available
Table Survey : user_id, survey_id, credits_required

Now I want to calculate the difference between credits_available and credits_required for a particular user_id and specified survey_id ? Is it possible to write a single query instead of calculating separately by 2 different queries?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-24T17:24:48+00:00Added an answer on May 24, 2026 at 5:24 pm

    MySQL lets you use normal math…

    SELECT (survey.credits_required - users.credits_available) as endResult
    FROM users,survey 
    WHERE users.user_id = survey.user_id 
    AND survey_id = $surveyID
    AND users.user_id = $userID
    

    And of course, $surveyID is a variable which lists the survey ID in question… $userID is a variable which lists the user ID in question…

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

My setup is as follows: Table 'data': 'title','body',...,'user_id',... Table 'users': 'user_id','some_val'... Basically I want
I have two tables: Users: ID, first_name, last_name Networks: user_id, friend_id, status I want
I want to do the following. Lock a row in the Users table for
I have a basic users table I want to create in MySQL. I do
CREATE TABLE users ( user_id INT(8) NOT NULL AUTO_INCREMENT, user_name VARCHAR(30) NOT NULL, user_pass
TABLE GROUP group_id | user_id 1 1 TABLE USERS user_id | fullname 1 Juan
Say I have a table like this: create table users ( user_id int not
I have a USERS table like this USERS user_id | username 1 tom 2
I have tables as below. Table Messages message_id parent_id forum_id user_id Table Users user_id
I want to do something like this: create table app_users ( app_user_id smallint(6) not

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.