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Home/ Questions/Q 190767
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:17:03+00:00 2026-05-11T16:17:03+00:00

@TableGenerator(name = trial, table = third, pkColumnName = a , valueColumnName = b, pkColumnValue

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@TableGenerator(name = "trial", table = "third",
        pkColumnName = "a" , valueColumnName = "b", pkColumnValue = "first")

@Entity

public class First{

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE, generator = "trial")
    protected int a;

    @OneToMany(mappedBy ="first", cascade = CascadeType.PERSIST)
    @JoinColumn(name = "a")
    protected List<Second> seconds;
}

@Entity

public class Second{

    @Id
    protected int a;

    @ManyToOne
    @JoinColumn(name = "b")
    First first;
}

When I run the following in main:

Second aSecond = new Second();

aSecond.a = 2;

First aFirst = new First();

List<Second> scnds = new ArrayList<Second>();
scnds.add(aSecond);

aFirst.seconds = scnds;

aEntityManager.getTransaction().begin();

aEntityManager.persist(aFirst);

aEntityManager.getTransaction().commit();

It set null in the column “b” in table second?
How can I get the value that is auto-created in a in First to set in b in Second?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:17:03+00:00Added an answer on May 11, 2026 at 4:17 pm

    A couple of things:

    First: You do not need the @JoinColumn(name = “a”) annotation on the seconds collection in the First class. The mapping is being handled by the Second class.

    Next:

    Second aSecond = new Second();
    aSecond.a = 2;
    First aFirst = new First();
    
    //its a bi-directional mapping so you have to set the references both ways
    aFirst.seconds.add(aSecond);
    aSecond.first = aFirst;
    
    aEntityManager.getTransaction().begin();
    aEntityManager.persist(aFirst);
    aEntityManager.getTransaction().commit();
    
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