Home/ Questions/Q 6681059
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-26T04:32:50+00:00

<%@taglib prefix=c uri=http://java.sun.com/jsp/jstl/core %> <%@taglib prefix=sql uri=http://java.sun.com/jstl/sql %> <sql:setDataSource var=dataSource driver=com.mysql.jdbc.Driver url=jdbc:mysql://localhost/cloud user=root password=root

  • 0
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@taglib prefix="sql" uri="http://java.sun.com/jstl/sql" %>

<sql:setDataSource var="dataSource" driver="com.mysql.jdbc.Driver"
url="jdbc:mysql://localhost/cloud" user="root"  password="root"
scope="session" /> 

<sql:query var="qryProvider" >
    SELECT * FROM `provider`;
</sql:query>

<table>
    <c:forEach var="row" items="${qryProvider.rows}">
        <tr>
            <td>${row.display_name}</td>

        </tr>
    </c:forEach>
</table>

I got the following error:

HTTP Status 500 -

type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: An exception occurred processing JSP page /testJSTL.jsp at line 8

5: url="jdbc:mysql://localhost:3306/cloud" user="root"  password="root"
6: scope="session" /> 
7:  
8: <sql:query var="qryProvider" >
9:     SELECT * FROM `provider`;
10: </sql:query>
11:  


Stacktrace:
    org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:567)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:456)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:333)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause

javax.servlet.ServletException: javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "java.lang.NullPointerException"
    org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:911)
    org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:840)
    org.apache.jsp.testJSTL_jsp._jspService(testJSTL_jsp.java:94)
    org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:433)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:333)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:722)

I tried to follow this tut, but it gives me an error if I write

<sql:query var="qryProvider" dataSource="${dataSource}" >

I’m new to this, could someone point me in the right direction?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    My advice would be to forget about the <sql> tags completely, and to make all your database operations in plain Java (in a servlet or action of your preferred MVC framework). This servlet would build a list of bean instances, ready to be displayed by your JSP. Use RequestDispatcher to dispatch the request to the JSP from the servlet.

    Even the official Java EE tutorial says:

    The JSTL SQL tags for accessing databases listed in Table 7-7 are
    designed for quick prototyping and simple applications. For production
    applications, database operations are normally encapsulated in
    JavaBeans components.

    • 0