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Home/ Questions/Q 500605
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:06:16+00:00 2026-05-13T06:06:16+00:00

Take a look at the following code: Number.prototype.isIn = function () { for (var

  • 0

Take a look at the following code:

Number.prototype.isIn = function () {
    for (var i = 0, j = arguments.length; i < j; ++i) {
        if (parseInt(this, 10) === arguments[i]) {
            return true;
        }
    }
    return false;
};

var x = 2;
console.log(x.isIn(1,2,3,4,5)); // <= 'true'
console.log(2.isIn(1,2,3,4,5)); // <= Error: 'missing ) after argument list'

Why is it that when it’s a variable, the code works correctly yet when it is a number literal, it fails ?


And also, strangely enough, why does the following line work?

console.log((2).isIn(1,2,3,4,5)); // <= 'true'

In the above line, I basically enclosed the literal in parenthesis.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:06:16+00:00Added an answer on May 13, 2026 at 6:06 am

    It’s a syntax error because you are representing a number. Strings can work that way, but not numbers, because a period immediately following a number symbolizes a decimal value. The character after the . is causing the error.

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