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Home/ Questions/Q 664989
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:39:38+00:00 2026-05-13T23:39:38+00:00

take a look at this code: $(document).ready(function() { document.getElementById(sliderId).onmousedown = sliderMouseDown; }); function sliderMouseDown()

  • 0

take a look at this code:

$(document).ready(function() {
    document.getElementById(sliderId).onmousedown = sliderMouseDown;
});

function sliderMouseDown() {
    document.onmousemove = sliderMouseMove; 
    document.onmouseup   = sliderMouseUp;
}

function sliderMouseMove() {
    $('#test').html("sliding");
}

function sliderMouseUp() {
    $('#test').html("not sliding");
    document.removeEventListener('mousemove', sliderMouseMove, false);
    document.removeEventListener('mouseup', sliderMouseUp, false);
}

Everything works as it should, until the sliderMouseUp function is called. Now, the function is called alright, and the #test-div says “not sliding”, but if I move my mouse around in the document afterwards, it displays “sliding” in the #test-div again, like if the removeEventListener function does not work. Am I doing something wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:39:39+00:00Added an answer on May 13, 2026 at 11:39 pm

    If jQuery is an option, and seems it is since you’re using it, do this:

    $(function() {
      $("#" + sliderId).mousedown(function() { 
        $(document).mousemove(function() { 
          $("#test").html("sliding");
        }).mouseup(function() {
          $("#test").html("not sliding");
          $(document).unbind("mousemove mouseup");
        });
      });
    });
    

    Using the jQuery event model will result in a lot less hair-pulling, let it take care of the cross-browser and event quirks for you.

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