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Home/ Questions/Q 990077
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:53:32+00:00 2026-05-16T05:53:32+00:00

Take a look at this code: #include <iostream> using namespace std; class A {

  • 0

Take a look at this code:

#include <iostream>

using namespace std;

class A
{
private:
    int privatefield;
protected:
    int protectedfield;
public:
    int publicfield;
};

class B: private A
{
private:
    A a;
public:
    void test()
    {
        cout << this->publicfield << this->protectedfield << endl;
    }
    void test2()
    {
        cout << a.publicfield << a.protectedfield << endl;
    }
};

int main()
{
    B b;
    b.test();
    b.test2();
    return 0;
}

B has access to this->protectedfield but hasn’t to a.protectedfield. Why? Yet B is subclass of A.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:53:33+00:00Added an answer on May 16, 2026 at 5:53 am

    B has access only to the protected fields in itself or other objects of type B (or possibly derived from B, if it sees them as B-s).

    B does not have access to the protected fields of any other unrelated objects in the same inheritance tree.

    An Apple has no right to access the internals of an Orange, even if they are both Fruits.

    class Fruit
    {
        protected: int sweetness;
    };
    
    class Apple: public Fruit
    {
        public: Apple() { this->sweetness = 100; }
    };
    
    class Orange: public Fruit
    {
    public:
        void evil_function(Fruit& f)
        {
            f.sweetness = -100;  //doesn't compile!!
        }
    };
    
    int main()
    {
        Apple apple;
        Orange orange;
        orange.evil_function(apple);
    }
    
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