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Home/ Questions/Q 468489
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T23:41:13+00:00 2026-05-12T23:41:13+00:00

Take a look: for ($i=1; $i<=$nr_of_pics; $i++) { ${‘image_src’ . $i} = $image_id.’_’.$i; $img_array

  • 0

Take a look:

for ($i=1; $i<=$nr_of_pics; $i++) {
        ${'image_src' . $i} = $image_id.'_'.$i;
        $img_array = imageSize(${'image_src' . $i}, $i, $category);


    }

and here is the imageSize function (simplified):

$myarr = array();
    $myarr['thumb_image_' . $nr . '_width'] = $thumb_width;
    $myarr['thumb_image_' . $nr . '_height'] = $thumb_height;
    $myarr['image_' . $nr . '_width'] = $width;
    $myarr['image_' . $nr . '_height'] = $height;
    return $myarr;

The function gets called and OWERWRITES the value of the $img_array inside the foor-loop, but I need it to ‘increment’ and add values after another in every loop.
So basically, it replaces its value every time it loops.
What should I do here?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-12T23:41:13+00:00Added an answer on May 12, 2026 at 11:41 pm

    You’re overwriting $img_array each time through the loop. Try changing

    $img_array = imageSize(${'image_src' . $i}, $i, $category);
    

    to

    $img_array[] = imageSize(${'image_src' . $i}, $i, $category);
    

    This will add an element to $img_array instead of replacing its value.

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