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Home/ Questions/Q 8360635
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T11:31:01+00:00 2026-06-09T11:31:01+00:00

Take an example function here: function a(b){ console.log(b != null ? 1 : 2);

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Take an example function here:

function a(b){
    console.log(b != null ? 1 : 2);
}

That code works fine, by printing 1 if you pass a parameter, and 2 if you don’t.

However, JSLint gives me a warning, telling me to instead use strict equalities, i.e !==. Regardless of whether a parameter is passed or not, the function will print 1 when using !==.

So my question is, what is the best way to check whether a parameter has been passed? I do not want to use arguments.length, or in fact use the arguments object at all.

I tried using this:

function a(b){
    console.log(typeof(b) !== "undefined" ? 1 : 2);
}

^ that seemed to work, but is it the best method?

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  1. Editorial Team
    Editorial Team
    2026-06-09T11:31:02+00:00Added an answer on June 9, 2026 at 11:31 am

    When no argument is passed, b is undefined, not null. So, the proper way to test for the existence of the argument b is this:

    function a(b){
        console.log(b !== undefined ? 1 : 2);
    }
    

    !== is recommended because null and undefined can be coerced to be equal if you use == or !=, but using !== or === will not do type coercion so you can strictly tell if it’s undefined or not.

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