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Home/ Questions/Q 6801605
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:07:14+00:00 2026-05-26T19:07:14+00:00

Taken from this answer here : static const qi::rule<std::string::iterator, ast_t()> node = ‘{‘ >>

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Taken from this answer here:

static const qi::rule<std::string::iterator, ast_t()> node = 
'{' >> *node >> '}' | +~qi::char_("{}");

Note that a constant var of name node is declared, but node is used to initialize this constant.

What’s going on here?

Helpful “Similar Questions” shows that it is valid in C++ in general, but what does it do in this spirit expression?

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:07:15+00:00Added an answer on May 26, 2026 at 7:07 pm

    It’s a recursive definition, very similar to this example with linked lists. A grammar rule is constructed which refers back to itself. It works because operator* takes its argument by (const) reference.

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