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Home/ Questions/Q 7169647
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T15:02:44+00:00 2026-05-28T15:02:44+00:00

Teaching myself C and finding that when I do an equation for a temp

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Teaching myself C and finding that when I do an equation for a temp conversion it won’t work unless I change the fraction to a decimal. ie,

tempC=(.555*(tempF-32)) will work but tempC=((5/9)*(tempF-32)) won’t work.

Why?
According to the book "C Primer Plus" it should work as I’m using floats for both tempC and tempF.

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  1. Editorial Team
    Editorial Team
    2026-05-28T15:02:46+00:00Added an answer on May 28, 2026 at 3:02 pm

    It looks like you have integer division in the second case:

    tempC=((5/9)*(tempF-32))
    

    The 5 / 9 will get truncated to zero.

    To fix that, you need to make one of them a floating-point type:

    tempC=((5./9.)*(tempF-32))
    
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