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Home/ Questions/Q 740889
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:34:07+00:00 2026-05-14T08:34:07+00:00

test = ‘a’ test2 = ‘@a’.slice(0) test3 = ‘@a'[1] puts test.hash puts test2.hash puts

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test = 'a'
test2 = '@a'.slice(0)
test3 = '@a'[1]

puts test.hash
puts test2.hash
puts test3.hash

Output:

100
64
97

Is this a bug or am I misunderstanding how the hash method works? Is there a way to fix this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:34:07+00:00Added an answer on May 14, 2026 at 8:34 am

    The results of these expressions are not all the same data. Ruby 1.8 integers contain character numbers for single character indexing. This has been changed in Ruby 1.9, but slice(0) returns the first character of the string '@', not 'a'.

    In Ruby 1.8 (using irb):

    irb(main):001:0> test = 'a'
    => "a"
    irb(main):002:0> test2 = '@a'.slice(0)
    => 64
    irb(main):003:0> test3 = '@a'[1]
    => 97
    irb(main):004:0> test.hash
    => 100
    irb(main):005:0> test2.hash
    => 129
    irb(main):006:0> test3.hash
    => 195
    

    In Ruby 1.9.1:

    irb(main):001:0> test = 'a'
    => "a"
    irb(main):002:0> test2 = '@a'.slice(0)
    => "@"
    irb(main):003:0> test3 = '@a'[1]
    => "a"
    irb(main):004:0> test.hash
    => 1365935838
    irb(main):005:0> test2.hash
    => 347394336
    irb(main):006:0> test3.hash
    => 1365935838
    
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