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Home/ Questions/Q 8043785
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T05:01:11+00:00 2026-06-05T05:01:11+00:00

Test data 1: Abc.TestCase For TestCase By Abc.TestCase Using TestCase –> 2 matches 2:

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Test data

1: "Abc.TestCase For TestCase By Abc.TestCase Using TestCase"           --> 2 matches 
2: "(Abc.TestCase For TestCase By Abc.TestCase Using TestCase)"         --> 2 matches
3: "(TestCase For TestCase By Abc.TestCase Using TestCase)"             --> 3 matches
4: "(Abc.TestCase For TestCase By Abc.TestCase Using Xyz.TestCase.Sub)" --> 1 match
5: "(Abc.TestCase For TestCase By Abc.TestCase Using Xyz.TestCase1)"    --> 1 match

Target is to obtain the unqualified “TestCase”

have tried the following

[^.]\bTestCase\b[^.]

while this works it fails with 2 & 3 case where it returns “(TestCase” “TestCase)” as matches, which would then lead erroneous results in the replacement.

at a wit’s end for this !

would appreciate some help here.

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  1. Editorial Team
    Editorial Team
    2026-06-05T05:01:12+00:00Added an answer on June 5, 2026 at 5:01 am

    I think this is what you’re looking for:

    (?<!\.)\bTestCase\b(?!\.)
    

    In other words, you want to match the whole word TestCase (i.e., not preceded or followed another word character), but not if it’s immediately preceded or followed by .. Here’s a slightly neater version:

    (?<!\.\w)TestCase(?!\.\w)
    

    The way you wrote the question, it sounds like you also want to exclude matches that are preceded or followed by parentheses, like (TestCase or TestCase), but I finally realized you just don’t want to include the parens in the match. Replacing the negated character classes ([^.]) with negative lookarounds ( (?<!\.) and (?!\.]) ) meets that requirement because lookarounds don’t consume what they match.

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