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Editorial Team
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Asked: 2026-05-17T06:48:51+00:00

$test = sprintf(SELECT * FROM `table` WHERE `text` LIKE ‘%%s%’, mysql_real_escape_string(‘test’)); echo $test; output:

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$test = sprintf("SELECT * FROM `table` WHERE `text` LIKE '%%s%'", mysql_real_escape_string('test'));

echo $test;

output:

SELECT * FROM `table` WHERE `text` LIKE '%s

but it should output:

SELECT * FROM `table` WHERE `text` LIKE '%test%'
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1 Answer

  1. Editorial Team
    ... LIKE '%%%s%%'", mysql_real_escape_string('test'));

    To print the % character you need to escape it with itself. Therefore the first two %% will print the % character, while the third one is for the type specifier %s. You need a double %% at the end as well.

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