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Home/ Questions/Q 972163
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:04:46+00:00 2026-05-16T03:04:46+00:00

that i need to have converted into <div id=WhateverHolder> <div class=block> <div class=item first></div>

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that i need to have converted into

<div id="WhateverHolder">

<div class="block">
<div class="item first"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item last"></div>
</div>

<div class="block">
<div class="item first"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item last"></div>
</div>

</div>

I have looked for a plugin that can do this but to no avail what is the easiest way to do this in jQuery

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:04:47+00:00Added an answer on May 16, 2026 at 3:04 am

    You could use the jQuery function .slice(...):

    http://api.jquery.com/slice/

    var items = $("#WhateverHolder > div.item");
    
    var blockCount = 4;
    
    for (var i = 0; i < items.length; i+= blockCount) {
        var slice = items.slice(i,i + blockCount);      
    
        slice.first().addClass('first');
        slice.last().addClass('last');
    
        slice.wrapAll("<div class=\"block\"></div>");
    }
    

    It will make a new block on the nine’th element. And otherwise make it exactly as you want with first and last classes.

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