Question

That is a beginner question to understand where I might be wrong using the switch statement.
The task is as follows:
Write a program that accepts two integer values typed in by the user. Display the
result of dividing the first integer by the second, to three-decimal-place accuracy.
Remember to have the program check for division by zero.

To test whether the second operand is a 0, I have used switch statement (I know I could have done that with if…else). However, the program will still accept 0 as the operand I am unsure why this happens. If it tries to calculate the division by 0, the program will simply fail. Could you please give me a hint as to where I might be wrong? My code is below:

  #include <stdio.h>

  int main (void)

  {
         int a, b;


   printf ("Type two integer values: ");
   scanf ("%i %i", &a, &b);

   switch (a/b)
   {

   case 'b == 0':
        printf ("\n The divisor can't be 0.\n");

   break;

   default:
           printf ("The result of dividing %i by %i is %.3f\n", a, b,(float) a / b);

   break;
  }
  return 0;

  }

Thanks for your help!

Answer 1

 switch (b)
   {
   case 0:
        printf ("\n The divisor can't be 0.\n");

   break;
   default:
           printf ("The result of dividing %i by %i is %.3f\n", a, b,(float) a / b);
   break;
  }

Also note, the expressions following case must be constants such as:

case 0:
case 1:
case 'a':
case 'b':

etc

There.. that should fix it.