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Asked: May 10, 20262026-05-10T22:49:10+00:00 2026-05-10T22:49:10+00:00

That was helpful kgiannakakis. I’m facing a problem as below: a = [‘zbc’,’2.3′] for

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That was helpful kgiannakakis. I’m facing a problem as below:

a = ['zbc','2.3'] for i in range(0,5):     exec('E%d=%s' %(i,a[i])) 

This results in:

 Traceback (most recent call last):   File '', line 2, in      exec('E%d=%s' %(i,a[i]))   File '', line 1, in  NameError: name 'zbc' is not defined 
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  1. 2026-05-10T22:49:10+00:00Added an answer on May 10, 2026 at 10:49 pm

    It looks like the code you’re generating expands to:

    E0=zbc E1=2.3 

    At the next iteration through the loop, you’ll get an IndexError exception because a is only two elements long.

    So given the above, you are trying to assign the value of zbc to E0. If zbc doesn’t exist (which it seems that it doesn’t), then you will get the NameError you mention.

    It’s hard to determine what you’re actually trying to do with this code, so I’m not sure what to recommend. You could assign strings instead:

    exec('E%d='%s'' %(i,a[i])) 

    This would expand to:

    E0='zbc' E1='2.3' 

    You would still get the IndexError because your array a is not 5 elements long. That should be an easy fix for you.

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