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Home/ Questions/Q 7176555
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T16:31:58+00:00 2026-05-28T16:31:58+00:00

The animation (image changes) doesn’t stop on the onmouseout event. Why? JavaScript: function thumbnail

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The animation (image changes) doesn’t stop on the onmouseout event. Why?

JavaScript:

function thumbnail ( type, start, i, m, id, begin, end ) 
{
    if ( type == 1 ) 
    {
        document.getElementById(id).src = begin + id + i + end;

        if ( i == m + 1 ) 
        {
            document.getElementById(id).src = begin + id + end;
            i = 2;
        } 
        else 
        {
            i++;
        }

        setTimeout("thumbnail(1, "+start+", "+i+", "+m+", '"+id+"', '"+begin+"', '"+end+"');", 1000 );
    }

    if ( type == 2 ) 
    {
        document.getElementById(id).src = begin + id + end;
    }
}

HTML:

<img id="aaa" src="http://example.com/file/aaa.png" width="160" height="120" onmouseover="thumbnail(1,2,2,9,'aaa','http://example.com/file/','.png');" onmouseout="thumbnail(2,2,2,9,'aaa','http://example.com/file/','.png');" />

Images:

aaa.png, aaa2.png, …, aaa9.png

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T16:31:59+00:00Added an answer on May 28, 2026 at 4:31 pm

    Try something like this:

    var delay;
    
    function thumbnail ( type, start, i, m, id, begin, end ){
      if ( type == 1 ){
        document.getElementById(id).src = begin + id + i + end;
        if ( i == m + 1 ){
          document.getElementById(id).src = begin + id + end;
          i = 2;
        } 
        else{
          i++;
        }
        if(delay) clearTimeout('delay');
        delay = setTimeout("thumbnail(1, "+start+", "+i+", "+m+", '"+id+"', '"+begin+"', '"+end+"');", 1000 );
      }
      if ( type == 2 ){
        document.getElementById(id).src = begin + id + end;
        clearTimeout('delay');
      }
    }
    
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