Question

THE ANSWER THAT WORKED FOR ME BASED ON AN ANSWER GIVEN

while($post = mysql_fetch_array($tags)) {
        $push = explode(',', $post['tags']);
        $array = array_merge($array, $push);
}

So I’m trying to display tags from my data base and make links out of them like this:

<?
$tags = mysql_query( 'SELECT tags  FROM `Table`');
$array = array();
while($post = mysql_fetch_array($tags)) {
$push = explode(',', $post['tags']);
array_push($array, $push);
}
foreach ($array as $value) {?>
    <a href="url.php?tags=<? echo $value?>"><? echo $value?></a>
<? }
?>

However all I get back is

    <a href="url.php?tags=Array">Array</a>

Where I should be having at least three lines as was previously produced by

<?
$tags = mysql_query( 'SELECT tags  FROM `Table`');
while($post = mysql_fetch_array($tags)) {
$array = explode(',', $post['tags']);
foreach ($array as $value) {?>
<a href="url.php?tags=<? echo $value?>"><? echo $value?></a>
<? }
}
?>

The code being called looks like this:

tag1, tag2, tag3

Tried

while($post = mysql_fetch_array($tags)) {
    $push = explode(',', $post['tags']);
array_merge($array, $push);
}
foreach ($array as $value) {?>
<a href="index.php?tags=<? echo $value?>"><? echo $value?></a>

now foreach doesn’t return a value

Answer 1

Use array_merge(), because array_push() will push the output of explode(), which is an array, as a whole to the array in the first argument, creating a jagged array.

As for your edit, this works:

$array = array_merge($array, $push);

foreach ($array as $value)
{
    echo '<a href="url.php?tags=' . $value . '">' . $value . '</a>';
}

Please note that array_merge() (contrary to array_push(), gotta love the consistency) does not alter the array passed as its first argument, so you’ll have to store the return value which I do on the first line ($array = ...).

While outputting to HTML, you also might want to put a $value = htmlentities(trim($value)); in the foreach loop.