Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The below code will obviously search for similar results as the query variable but what is the SQL command to search for exact results and not “like”?
$query = "SELECT languages.language FROM languages WHERE language LIKE '%".$name."%'";
have you tried the
=operator and removing the%wild cards?