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Home/ Questions/Q 581559
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:35:31+00:00 2026-05-13T14:35:31+00:00

The below code works properly, but it is hard coded. I would like to

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The below code works properly, but it is hard coded. I would like to be able to create an array of field sets, hide those fields, then each time I click on the “#createEventForm-eventInformation-addElement” button it displays the next one. The problem with the below code is that it is hard coded and thus would break easily and be much larger than using loops. Can someone help me make this better.

$("#fieldset-group1").hide();
$("#fieldset-group2").hide();
$("#fieldset-group3").hide();
$("#fieldset-group4").hide();
$("#fieldset-group5").hide();
$("#fieldset-group6").hide();
$("#fieldset-group7").hide();
$("#fieldset-group8").hide();
$("#fieldset-group9").hide();

$("#createEventForm-eventInformation-addElement").click( 
  function() { 
      ajaxAddEventInformation();
      if($("#fieldset-group1").is(":hidden"))
      {
          $("#fieldset-group1").show();
      }
      else
      {
          $("#fieldset-group2").show();
      }


   }
);
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  1. Editorial Team
    Editorial Team
    2026-05-13T14:35:31+00:00Added an answer on May 13, 2026 at 2:35 pm

    You should use the ^= notation of the jquery selectors which means starting with ..

    // this will hide all of your fieldset groups
    $('[id^="fieldset-group"]').hide(); 
    

    Then

    $("#createEventForm-eventInformation-addElement").click( 
      function() { 
          ajaxAddEventInformation();
          // find the visible one (current)
          var current = $('[id^="fieldset-group"]:visible');
          // find its index
          var index = $('[id^="fieldset-group"]').index( current ); 
          // hide the current one
          current.hide(); 
          // show the next one
          $('[id^="fieldset-group"]').eq(index+1).show(); 
       }
    );
    
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