Home/ Questions/Q 3217944
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-17T15:28:13+00:00

The book of IronPython In Action has the following code to read python script

  • 0

The book of IronPython In Action has the following code to read python script into a string. (Chapter 15.2)

static string GetSourceCode(string pythonFileName)
{
    Assembly assembly = Assembly.GetExecutingAssembly();
    Stream stream = assembly.GetManifestResourceStream(pythonFileName);
    StreamReader textStreamReader = new StreamReader(stream);
    return textStreamReader.ReadToEnd();
}

It reads BasicEmbedding.source_code.py to a string. I just copied to my code, but I got the following error. (Just running from example code is OK)

Unhandled Exception: System.ArgumentNullException: Argument cannot be null.
Parameter name: stream
  at System.IO.StreamReader.Initialize (System.IO.Stream stream, System.Text.Encoding encoding, Boolean detectEncodingFromByteOrderMarks, Int32 bufferSize) [0x00000] in :0 
  at System.IO.StreamReader..ctor (System.IO.Stream stream, System.Text.Encoding encoding, Boolean detectEncodingFromByteOrderMarks, Int32 bufferSize) [0x00000] in :0 
  at System.IO.StreamReader..ctor (System.IO.Stream stream) [0x00000] in :0 
  at (wrapper remoting-invoke-with-check) System.IO.StreamReader:.ctor (System.IO.Stream)
  at BasicEmbedding.Program.GetSourceCode (System.String pythonFileName) [0x00000] in :0 
  at BasicEmbedding.Program.Main () [0x00000] in :0

I think I can implement the same function as follows, which works OK.

static string GetSourceCode(string pythonFileName)
{
    Assembly assembly = Assembly.GetExecutingAssembly();
    string path = assembly.Location;
    string rootDir = Directory.GetParent(path).FullName;
    string pythonScript = Path.Combine(rootDir, pythonFileName);

    StreamReader textStreamReader = File.OpenText(pythonScript);

    return textStreamReader.ReadToEnd();
}

Question

  • For the original code, what’s for the “assembly.GetManifestResourceStream()” function, and why do I get the error?
  • Is my new code the same as the old code in terms of execution result?
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    • For the original code, what’s for the “assembly.GetManifestResourceStream()” function, and why do I get the error? : It looks for an embedded resource compiled into your application with the given name. Most likely, you are not adding a resource with that name.

    • Is my new code the same as the old code in terms of execution result? : No. Your reads a file from disk with the given name, in the same directory as the assembly. The original reads a resource from within the assembly.

    • 0