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Home/ Questions/Q 1094169
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:56:03+00:00 2026-05-16T23:56:03+00:00

The C# 4.0 compiler does not complain about this (not even a warning): if(10.0

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The C# 4.0 compiler does not complain about this (not even a warning):

if(10.0 > null + 1)
{       
}

if (myDoubleValue > null)
{
}

And it seems to be always false. What is going on here? Is null automatically converted to Nullable<double> or something?

If so why doesn’t this work then:

double myDoubleValue = null + 1;

Also, why would I ever want such a behavior. Why is it a good thing that it is possible playing around with literals like this.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:56:04+00:00Added an answer on May 16, 2026 at 11:56 pm

    The reason the assignment doesn’t work is that the result is of type double?, not double. The result will always be the null value for the double? (aka Nullable<double>) type.

    Oh, and both of the first two blocks should make the compiler complain, with warnings like this:

    Test.cs(7,19): warning CS0458: The
    result of the expression is always
    ‘null’ of type ‘int?’
    Test.cs(12,13):
    warning CS0464: Comparing with null of
    type ‘double?’ always produces ‘false’

    Managing to compile without errors isn’t the same as not complaining 🙂

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