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Asked: May 11, 20262026-05-11T12:09:04+00:00 2026-05-11T12:09:04+00:00

The code Assert.AreEqual (9.97320998018748d, observerPosition.CenterLongitude); produces Expected Value & Actual Value : 9.97320998018748 Remark

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The code

Assert.AreEqual (9.97320998018748d, observerPosition.CenterLongitude); 

produces

Expected Value & Actual Value : 9.97320998018748 Remark : Both values look the same when formatted but they  are distinct instances. 

What is the most elegant way to compare two doubles for equality in MbUnit 3.0? I know I could round them up myself, but is there some MbUnit construct for this?

UPDATE: I consider my current ‘workaround’ to be non-elegant:

Assert.LessThan(    Math.Abs(9.97320998018748d - observerPosition.CenterLongitude),    0.0000001); 
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  1. 2026-05-11T12:09:05+00:00Added an answer on May 11, 2026 at 12:09 pm

    AreApproximatelyEqual seems to be the ‘MbUnit construct for this’:

    Verifies that an actual value approximately equals some expected value to within a specified delta.

    This seems to be similar to Assert.AreEqual(double expected, double actual, double delta)

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