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Home/ Questions/Q 6962387
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T15:39:14+00:00 2026-05-27T15:39:14+00:00

The code below can checks if the image is visible or not. $(‘#div1 img:visible’)

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The code below can checks if the image is visible or not.

$('#div1 img:visible')

Which selects all image descendants and:

$('#div1 > img:visible')

I just need to know that when I iterate over every image in a container like dgImages $("#dgImages] img").each(function () {} how I can determine that the image is visible or not ? Can I write something like if($(this:visible)){//Do something}?. Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T15:39:15+00:00Added an answer on May 27, 2026 at 3:39 pm
    $("#dgImages").find('img').each(function(){
       if($(this).is(':visible')){
         alert("This image is visible");
        }
    });
    
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