Question

The code below searches my mysql database and comes back with postcodes like IG6,RM11,RM8,RM4,RM2,RM6,RM7,RM1,RM5 and a distance using a stored procedure. (All ok)

PROBLEM: With these results, I want to search another table in same database that may have job information with those Postcodes (probably using LIKE).

What’s the best way to get this working? I have tried many examples (implode, arrays, etc)
Is one connection to database correct? How do I query the variable as it does come back with 2 columns, postcode and Distance. Should I split in an array (how?)

END PRODUCT: HGV Driver RM5, Cleaner RM5, Teacher RM5

(SELECT title FROM jobinfo WHERE location IN results from other query);

 <?php
    include ("conn.php");
    $first="RM5";

    $result = mysql_query("select outcode, GetDistance(Lat, Lon, (SELECT Lat from postcodes where outcode = '$first' limit 1),(SELECT Lon from postcodes where outcode = '$first' limit 1)) as Distance from postcodes having Distance < 3 order by Distance DESC;");
    while($row = mysql_fetch_array($result))
    {
        echo  ($row['outcode']) ;
    } 
    // This returns postcodes

    $resultb = mysql_query("SELECT title FROM jobinfo WHERE location IN ($results[outcode]) ");
    while($row = mysql_fetch_array($resultb))
    {
        echo  ($row['title']) ;
    }
    mysql_close($con);
?> 

Please help…..any reference to join table needs full explanation as all so far don’t help!

Answer 1

First Prepare the output into the clause:

in the first while loop:

while($row = mysql_fetch_array($result))
 {
    $array[] = $row['outcode'] ;
 } 

Then prepare the array for the IN clause:

foreach ($array as $a) {$clause.= "'$a',";}
$clause=substr($clause,0,-1)

Finally use the clause for the IN statement:

$resultb = mysql_query("SELECT title FROM jobinfo WHERE location IN ($clause) "

===== EDIT === LIKE statement

For like.. you need multiple like statement OR together.. Using SQL LIKE and IN together

Change the prepare clause code to this:

foreach ($array as $a) {$clause.= " location LIKE '%$a%' OR";}
$clause=substr($clause,0,-3)

AND the sql becomes:

$resultb = mysql_query("SELECT title FROM jobinfo WHERE $clause ");

Of course you will want to addin some more error checking.. think of the possible injection.