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Home/ Questions/Q 8072359
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T13:59:38+00:00 2026-06-05T13:59:38+00:00

The code below shows 2 Foo templates each with 2 default parameters, Foo1 has

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The code below shows 2 Foo templates each with 2 default parameters, Foo1 has a separate prototype and Foo2 doesn’t, they are otherwise the same.

Why will the first call into Foo1 cause the compiler (VS2010 Native C++) to produce an error while the other 3 work?

#include <limits>

// not needed but to prevent answers in this direction...
#undef max
#undef min

template< typename T >
void Foo1( T v1 = std::numeric_limits< T >::min(), T v2 = std::numeric_limits< T >::max() );

template< typename T >
inline
void Foo1( T v1, T v2 )
{
    // ...
}

template< typename T >
inline
void Foo2( T v1 = std::numeric_limits< T >::min(), T v2 = std::numeric_limits< T >::max() )
{
    // ...
}

int main()
{
    Foo1<int>(0);  /* Will cause  error C2589: '::' : illegal token on right side of '::' */
    Foo1<int>(0, 10);  
    Foo2<int>(0);
    Foo2<int>(0, 10);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T13:59:39+00:00Added an answer on June 5, 2026 at 1:59 pm

    This is a compiler bug as reported here. The workaround seems to be:

    Thank you for submitting this feedback. While we recognize that this is a valid compiler bug, it is below our triage bar at this point in the product cycle. The workaround is to define the template function where you have declared it. If you are concerned about the perf impact of recompiling the template function for each translation unit, using PCH files should eliminate this overhead.

    Thanks,
    Mark Roberts
    Visual C++ Team

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