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Editorial Team
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Asked: 2026-05-28T14:11:57+00:00

The code: `cat <(fgrep -i -v $DAEMON_TEST <(sudo -u asm crontab -l)) <(echo $CRON)

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The code:

`cat <(fgrep -i -v "$DAEMON_TEST" <(sudo -u asm crontab -l)) <(echo "$CRON") | sudo -u asm crontab -`

The error:

command substitution: line 46: syntax error near unexpected token `('
/etc/init.d/asm: command substitution: line 46: `cat <(fgrep -i -v "$DAEMON_TEST" <(sudo -u asm crontab -l)) <(echo "$CRON") | sudo -u asm crontab -'

The command runs fine when run directly into the shell by replacing the variables with the relevant strings

Here are the variables:

DAEMON_TEST=asm_test.php
CRON="*/15 * * * * /opt/asm/daemons/test.php"
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1 Answer

  1. Editorial Team

    The issue ended up being completely unrelated.

    Changed:

    #/bin/sh

    to:

    #/bin/bash

    I never realized there would be a differnce

    https://superuser.com/questions/125728/what-is-the-difference-between-bash-and-sh

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