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Home/ Questions/Q 8735123
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T09:58:54+00:00 2026-06-13T09:58:54+00:00

The code – for(int i = 0; i < count; i++) { System.out.println(Please enter

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The code –

for(int i = 0; i < count; i++)
    {
     System.out.println("Please enter a number!");
    try{
         numbers[i] = keyboardScanner.nextInt();
    }catch(InputMismatchException ex)
    {
      System.out.println("You did not enter a number!");
    }
}

If you enter a String, it loops till ‘count’. Why does that happen ?

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  1. Editorial Team
    Editorial Team
    2026-06-13T09:58:56+00:00Added an answer on June 13, 2026 at 9:58 am

    Sure, it’ll loop until count: you caught the exception and continued the loop anyway.

    You want to break out of your loop when you get that exception:

    System.out.println("You did not enter a number!");
    break;
    
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