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Home/ Questions/Q 8552849
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T14:31:08+00:00 2026-06-11T14:31:08+00:00

The Code is as follow : The Code : #include <iostream> using namespace std;

  • 0

The Code is as follow :

The Code :

#include <iostream>

using namespace std;

class Animal{
   int a;

    public:
    Animal(int a) : a(a){}
    int geta(){return a;}
};

class Bird : virtual public Animal{
    string b;
    public:
    Bird(int a , string b) : Animal(a) , b(b){}
};

class Fish : virtual public Animal{
    int f;
    public:
    Fish(int a , int f) : Animal(a) , f(f){}
};

class Unknown : public Bird, public Fish{
    char u;
    public:
    Unknown(int a , int f , string b , char u )
     : Bird(a , b) , Fish(a , f) , u(u){}  //Problem
};

The Question :

1.)How am I going to initialize all the superclass if the Unknown class is instantiated?Since there’s only one instance of Animal will be created , how can I avoid mysef from having to call its constructor twice ?

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  1. Editorial Team
    Editorial Team
    2026-06-11T14:31:09+00:00Added an answer on June 11, 2026 at 2:31 pm

    The most derived class initializes any virtual base classes. In your class hierarchy, Unknown must construct the virtual Animal base class (e.g. by adding Animal(a) to its initialization list).

    When constructing an Unknown object, neither Fish nor Bird will call the Animal constructor. Unknown will call the constructor for the Animal virtual base.

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