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Home/ Questions/Q 9138923
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T09:19:12+00:00 2026-06-17T09:19:12+00:00

The code is pretty straight forward, however it is just not running the way

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The code is pretty straight forward, however it is just not running the way it is expected to, basically the numbers get added at the end in order to continue the while loop. But they are just not adding, the $two and $i that is

PHP:

$i=1;
$two=2;
$add=9;
$count=1;
while($i<=7488){
    echo $count;
    echo $exploded[$two];
    echo "<br>count=".$count."<br>";
    echo "<br>two=".$two."<br>";
    echo "<br>i=".$i."<br>";
    $count++;
    $two+$add;
    $i+$add;
}
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  1. Editorial Team
    Editorial Team
    2026-06-17T09:19:13+00:00Added an answer on June 17, 2026 at 9:19 am

    How about this:

    $two += $add;
    $i += $add;
    

    $two + $add is just an expression that returns the sum of the two variables; it doesn’t actually do anything or change any state.

    $two += $add (+= is the addition assignment operator) is equivalent to $two = $two + $add. Analogous operators exist for other arithmetic operations (e.g. *=, -=, etc.).

    This pattern is true for all C-like languages (to my knowledge), and many other languages too.

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