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Home/ Questions/Q 6624309
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:38:11+00:00 2026-05-25T21:38:11+00:00

The code: >>> mydict = {} >>> keylist = [‘a’,’b’,’c’] >>> mydict=dict.fromkeys(keylist,{}) >>> mydict[‘a’][‘sample’]

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The code:

>>> mydict = {}
>>> keylist = ['a','b','c']
>>> mydict=dict.fromkeys(keylist,{})
>>> mydict['a']['sample'] = 1
>>> mydict
{'a': {'sample': 1}, 'c': {'sample': 1}, 'b': {'sample': 1}}

I was expecting mydict['a']['sample'] = 1 would set the value just for a’s dictionary value and would get this: {'a': {'sample': 1}, 'c': {}, 'b': {}}.

What am I missing here? What should I have to do to get the expected output?

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:38:12+00:00Added an answer on May 25, 2026 at 9:38 pm

    The problem is that you added the same dictionary to mydict for every key. You want to add different dictionaries, like so:

    mydict = dict((key, {}) for key in keylist)
    

    In the above code, you create a new dictionary to pair with each key. In your original code, the function fromkeys took the argument (the empty dictionary you provided) and added that exact argument – that single empty dictionary you created to pass in to the function – to each of the keys. When that one dictionary was changed, then, that change showed up everywhere.

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