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Home/ Questions/Q 8833957
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T08:54:27+00:00 2026-06-14T08:54:27+00:00

The code that I have, public static void main(String[] args) { int x =

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The code that I have,

public static void main(String[] args) {
    int x = 27;
    int y = 5;
    double z = x / y;
    System.out.println(" x = " + x + " y = "+y +" z = "+z);
}

In the above code I know that to print out the decimal place .4 for the variable z we have to use printf, but my question is why does the variable z is not storing the 5.4 and just storing 5?
I mean int / int then the out put is stored in a double, which is perfectly capable of holding decimal values but it is not, what is the logic?

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  1. Editorial Team
    Editorial Team
    2026-06-14T08:54:28+00:00Added an answer on June 14, 2026 at 8:54 am

    This is happening because the values that you are dividing with are int and not double and they are not going to output the decimal places, to be more clear take this for example

    double z = 27 /5;
    same as yours

    double z = 27.0/5.0;
    now z = 5.4;
    So this shows that the datatype that you are performing calculation with also should be the same as the datatype you are expecting the output to be.

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