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Home/ Questions/Q 1033099
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:10:52+00:00 2026-05-16T14:10:52+00:00

The directory and file structure is as follows: C:\xampp\htdocs\PHP_Upload_Image_MKDIR\uploaded C:\xampp\htdocs\testA.php // as follows $userID

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The directory and file structure is as follows:

C:\xampp\htdocs\PHP_Upload_Image_MKDIR\uploaded
C:\xampp\htdocs\testA.php // as follows

$userID = 's002';
$uploadFolder = '/PHP_Upload_Image_MKDIR/uploaded/';
$userDir = $uploadFolder . $userID;
mkdir($userDir, 0700);

If I call testA.php, then the following folder will be created.

C:\PHP_Upload_Image_MKDIR\uploaded\s002

However, the desired result should be the following:

C:\xampp\htdocs\PHP_Upload_Image_MKDIR\uploaded\s002

I would like to know a decent method so that the mkdir creates folder relative to the root of the web

C:\xampp\htdocs\
or
C:\wamp\www

Then in the future, I don’t have problems to move this application to a web hosting site.

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:10:53+00:00Added an answer on May 16, 2026 at 2:10 pm

    You can:

    • Create a file with defines that’s always included and where you define what’s the server root (or whatever prefix) so that you prepend it to the directory.
    • Use a relative directory to the script. The directory of the script can be obtained with dirname(__FILE__).
    • Use a relative path to the current directory. The current directory, if not changed, is usually the directory of the PHP script that was originally called (usually not a good option).
    • Use $_SERVER[DOCUMENT_ROOT] (not a very good option, you might want your application in a subdirectory, and whether this value is available depends on the web server).
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