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Home/ Questions/Q 7428999
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T08:53:59+00:00 2026-05-29T08:53:59+00:00

The documentation for the keyword is states that: The is operator only considers reference

  • 0

The documentation for the keyword “is” states that:

The is operator only considers reference conversions, boxing
conversions, and unboxing conversions. Other conversions, such as
user-defined conversions, are not considered.

What does it mean in practice?
Is it wrong to use it to check if a struct is a certain type?
For example,

public struct Point2D
{
    public int X;
    public int Y;

    ...

    public override bool Equals(Object value)
    {
        if (value != null && value is Point2D)   // or if (value != null && GetType() == value.GetType())
        {
            Point2D right = (Point2D)value;
            return (X == right.X && Y == right.Y);
        }
        else return false;
    }

    ...
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T08:54:00+00:00Added an answer on May 29, 2026 at 8:54 am

    Checking whether a struct is a certain type is fine. The documentation means that user-defined explicit and implicit conversion operators are not evaluated when considering whether the given object is of the specified type, even if there is a user-defined operator that can convert it to said type.

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