Question

The end goal is to connect two query parameters that are being passed to a Play! web service request. It looks like:

WS
.url(requestUri)
.withQueryString(finalQueries)

I attempted to use a couple operators but it failed like so:

val finalQueries = queryParams match {
        case Some(queries) =>
          tokenParam ++ queries
        case None =>
          tokenParam
}

Error: value ++ is not a member of (String, String)

The API documentation shows that withQueryString accepts a (String, String)*

I’m a little confused with Play!’s withQueryString method since it does appear to complete replace the entire query string every time I access it. Any way to decently combine query strings?

Edit: A sample query string is below (the type syntax and its final appearance are a little confusing…):

val queryString = ("timeMin" -> "2012-08-20T01%3A11%3A06.000Z")

Answer 1

from your code, it seems to me that queryParams should be Option[(String, String)], and from the error message, tokenParam must be (String, String)
I think you can try this:

val finalQueries = Seq(tokenParam) ++ queryParams
WS
.url(requestUri)
.withQueryString(finalQueries:_*)

---

it works because Option can be treated as Seq, eg: Seq(1, 2) ++ Some(3) will become Seq(1, 2, 3) and Seq(1, 2) ++ None will be just Seq(1, 2)

and then .withQueryString accepts a (String, String)* means you can call it like .withQueryString(param1, param2, andMore),
or you can call it with a Seq and tell the compiler to treat it like anythingRepeated by writing : _* at the end of the Seq like .withQueryString(Seq(param1, param2, andMore): _*)