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Home/ Questions/Q 7981991
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T10:32:37+00:00 2026-06-04T10:32:37+00:00

The execv() function expects an array of NULL terminated strings but doesn’t take the

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The execv() function expects an array of NULL terminated strings but doesn’t take the number of arguments. It uses a sentinel value (NULL pointer) to determine when the array ends.

The man page for execv() states…

The first argument, by convention, should point to the filename
associated with the file being executed. The array of pointers must
be terminated by a NULL pointer.

… so my question is….

I want to pass the argv from main() to execv().

Can I be assured that argv that comes into main is terminated by a NULL pointer?
That is, can I be assured that argv[argc] == NULL or do I have to allocate my own char* array of size argc + 1 and put NULL in the argc index?

If I can be assured, is it documented somewhere?

Thanks,
~Eric

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  1. Editorial Team
    Editorial Team
    2026-06-04T10:32:38+00:00Added an answer on June 4, 2026 at 10:32 am

    Yes. The argv vector is always NULL terminated.

    The draft C99 standard states:

    If they are declared, the parameters to the main function shall obey the following
    constraints:

    • The value of argc shall be nonnegative.
    • argv[argc] shall be a null pointer.
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