Question

the fallowing code tells me that o.days and days from constructor can’t be solved, has anyone an idea why?

template <class T> struct Array{
    int days;
    T * M;
};

contructor of the class:

void constr(Array<Expe> &o){
        o=new Array;
        o->days = days;
        o->M = new Array[o->days];
}

EDIT (Luchian Grigore):

template <class T> struct Array{
int days;
T * M;
Array( int size ) : days(size), M(new int[size])
{
}
~Array()
{
   delete[] M;
}
};

when i try to init an array in main like this:

int main(){
//Main function of the program. no pre/ post condition.
Array <Expe> A;

error:

enter code here..\M.cpp:18:15: error: no matching function for call to ‘Array::Array()’

Answer 1

Array<Expe> &o is a reference to an Array<Expe> object, not a pointer. If you must re-initialize it, the syntax is.

o = Array<Expe>();

and you access the members via .:

o.days = days;
o.M = new Array[o.days];

EDIT:

I remember the same code from yesterday. Why are you agains using proper constructors?

template <class T> struct Array{
    int days;
    T * M;
    Array( int size ) : days(size), M(new int[size])
    {
    }
    ~Array()
    {
       delete[] M;
    }
};