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Home/ Questions/Q 9199875
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T22:38:16+00:00 2026-06-17T22:38:16+00:00

The file is available as raw data in the request. How am I supposed

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The file is available as raw data in the request. How am I supposed to transform it to be saved on the disk represented by the ImageField inside a model.

Tried stuff:

file_ = File(request)
modelinstance.picture.save(filename, file_, save=False)
modelinstance.save()

and some variants of the above. An example on how to do this inside the django view would help.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-17T22:38:18+00:00Added an answer on June 17, 2026 at 10:38 pm

    Solved it like this

    filename = request.GET[ 'yourfilename' ]
    
    from django.core.files.uploadedfile import SimpleUploadedFile
    file_contents = SimpleUploadedFile("%s" %(filename), request.raw_post_data)
    
    modelinstance.picture.save(filename, file_contents, True)
    
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