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Home/ Questions/Q 4067338
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Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T16:14:13+00:00 2026-05-20T16:14:13+00:00

The first one displays the div, the second one hides the dive up on

  • 0

The first one displays the div, the second one hides the dive up on clicking anywhere else in the document. the problem i have is, when i click the button to show the div, it also counts as a document click so it hides the div. how can i it make not hide the div when i click to show the div

<script type="text/javascript">
    function test22(){  

        var links = document.getElementById('links_safari');
        if(links.style.display == "none"){

            document.getElementById('links_safari').style.display="";
            var content = $('#links_safari').html();             
            var words = content.split(',');             
            for (var i = 2; i < words.length; i += 3) { 
                words[i] += '<br>'; 
            }
            content = words.join(' ');  
            $('#links_safari').html(content); 

            $('#links_safari').css("margin-top", -322);
            $('#links_safari').css("margin-left", 180);
            safariPopupStatus++;
        }
        else{
            links.style.display="none";

        }
    }



</script>

<script type="text/javascript">
    $(function (){

        $(document).click(

            function (e){
                var links = document.getElementById('links_safari');

                links.style.display="none";
                }  
        )
    })
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T16:14:14+00:00Added an answer on May 20, 2026 at 4:14 pm

    lets suppose the id of your button is showBtn the code now will be

    $(document).click(
    
                function (e){
                    if($(e.target).attr('id')=='showBtn') return
    
                    var links = document.getElementById('links_safari');
                    if(links.style.display != "none") // why not check here ?
                      links.style.display="none";
    
                    }  
            )
    
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